Figure 2.2a Multiple Forces on a Particle |
Figure 2.3a 2-force Experiment |
In Figure 2.3a a body A is acted upon by two forces. Assume
that the force R is given.
What must the magnitude and direction of force Fc
be, in order for the body A to remain at rest ?
The experimentalist will tell us immediately :
| The forces R and Fc must be exactly equal in value and exactly opposite in direction. |
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Going back to the business of
action/reaction : can you now think of an experiment
which clearly demonstrates that the force you are exerting on the
chair you are sitting on is equal and opposite to that the chair is exerting
on you ?
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Figure 2.4a 3-force Experiment |
After some experimenting one would find out that body A remains at rest whenever the forces Fa and Fb form the sides of a parallelogram the diagonal of which is equal
Figure 2.4b 3-force Experiment |
We call this diagonal force the resultant R
(in this case of Fa and Fb )
It has the same effect on the body A
as the original forces Fa and Fb,
namely to counter-balance Fc in the
same way R
did in the 2-force experiment of section 2.3.
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Figure 2.5a Resultant of 2 forces |
Above equations are directly related to the Law of Sines and Cosines .
How about you try to derive them yourself ? We need lots of trigonometry
in the weeks to come and this would be an exercise as good as any.
Speaking of trigonometry. Can you derive an equation for the
tan(β) ?
You have to be careful when applying equation 2.5b because it gives
you always two possible values for the angle
β because
in the ambiguity in determination of an angle with only its cosine is given.
(example
cos(β) = 0.5
has as solutions
β=60° and β=300 °)
The rule is that the resultant R has to lie always inbetween the given forces F1 and F2. Hence, you choose the angle β such that :
You definitely should look at
Problem 2.5a.
An important special case occurs when
F1 and F2 are equal in magnitude and the
angle α between them approaches 180°.
Maybe you can visualize the outcome from Figure 2.5a. Alternatively,
from Equation 2.5a we obtain that R=0.
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Figure 2.6a 3-force on a particle |
|
We could first replace for example Fa and Fb
by a resultant, say Rab, using
equation 2.5a to find its value and 2.5b
to find its orientation. Now we have only two forces left, Rab and Fc. We can find their resultant by using Equations 2.5a and 2.5b again. Obviously, this concept can be expanded to as many forces as we like. |
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Here is an alternative statement concerning the equilibrium of a particle :
| A particle remains at rest if the resultant of ALL forces acting on it is equal to zero. |
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In essence this is a special case of Newton's 2nd law :
where m is the mass of the particle, F is
the resultant of ALL forces acting on the particle, and a
is the corresponding acceleration (change of velocity) of the
particle.
In statics we want a=0 which requires that F=0.
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Prob. 2.8a : Resultant of 2 forces
Prob. 2.8b : Resultant of 3 forces
Prob. 2.8c : Equilibrium of particle
Prob. 2.8d : Resultant of 3 forces
Zig Herzog, hgn@psu.eduu
Last revised: 08/16/06